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答案:
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1.3.设j l=k
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2.casual'kæʒjʊəl]a
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3.j j j j j k
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4.[A][S][D][F][J][K][L][;]B.[S][D][F][G][H][J][K][L]C.[Caps Lock][A][S][D][K][L][;][']D.
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5.以下程序段的输出结果是:int k,j,s;for(k=2;k<6;k ,k ){ s=1;for(j=k;j<6;j )s =j;}printf("%d ",s);
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j==j>k);">6.int i,j,k;i=1;j=2;k=3;printf("%d\n",i>j==j>k);
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7.#includemain(){ int **k,*j,i=100; j=&i;k=&j; printf(“%d\n”,**k);}
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8.j z j z j z j z k
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9.for(i=1; i<=n; i ){for(j=1; j<=n; j ){c[i][j]=0;for(k=1; k<=n; k ){c[i][j] = c[i][j] a[i][k]*b[k][
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10.for (j=i l; j<=n;j X